2f^2-5f+12=0

Solution for 2f^2-5f+12=0 equation:

Simplifying
2f2 + -5f + 12 = 0

Reorder the terms:
12 + -5f + 2f2 = 0

Solving
12 + -5f + 2f2 = 0

Solving for variable 'f'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
6 + -2.5f + f2 = 0

Move the constant term to the right:

Add '-6' to each side of the equation.
6 + -2.5f + -6 + f2 = 0 + -6

Reorder the terms:
6 + -6 + -2.5f + f2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -2.5f + f2 = 0 + -6
-2.5f + f2 = 0 + -6

Combine like terms: 0 + -6 = -6
-2.5f + f2 = -6

The f term is -2.5f.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5f + 1.5625 + f2 = -6 + 1.5625

Reorder the terms:
1.5625 + -2.5f + f2 = -6 + 1.5625

Combine like terms: -6 + 1.5625 = -4.4375
1.5625 + -2.5f + f2 = -4.4375

Factor a perfect square on the left side:
(f + -1.25)(f + -1.25) = -4.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.